Integrand size = 19, antiderivative size = 136 \[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=-\frac {4 (c+d x)^{3/4}}{15 (b c-a d) (a+b x)^{15/4}}+\frac {16 d (c+d x)^{3/4}}{55 (b c-a d)^2 (a+b x)^{11/4}}-\frac {128 d^2 (c+d x)^{3/4}}{385 (b c-a d)^3 (a+b x)^{7/4}}+\frac {512 d^3 (c+d x)^{3/4}}{1155 (b c-a d)^4 (a+b x)^{3/4}} \]
[Out]
Time = 0.02 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {47, 37} \[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\frac {512 d^3 (c+d x)^{3/4}}{1155 (a+b x)^{3/4} (b c-a d)^4}-\frac {128 d^2 (c+d x)^{3/4}}{385 (a+b x)^{7/4} (b c-a d)^3}+\frac {16 d (c+d x)^{3/4}}{55 (a+b x)^{11/4} (b c-a d)^2}-\frac {4 (c+d x)^{3/4}}{15 (a+b x)^{15/4} (b c-a d)} \]
[In]
[Out]
Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = -\frac {4 (c+d x)^{3/4}}{15 (b c-a d) (a+b x)^{15/4}}-\frac {(4 d) \int \frac {1}{(a+b x)^{15/4} \sqrt [4]{c+d x}} \, dx}{5 (b c-a d)} \\ & = -\frac {4 (c+d x)^{3/4}}{15 (b c-a d) (a+b x)^{15/4}}+\frac {16 d (c+d x)^{3/4}}{55 (b c-a d)^2 (a+b x)^{11/4}}+\frac {\left (32 d^2\right ) \int \frac {1}{(a+b x)^{11/4} \sqrt [4]{c+d x}} \, dx}{55 (b c-a d)^2} \\ & = -\frac {4 (c+d x)^{3/4}}{15 (b c-a d) (a+b x)^{15/4}}+\frac {16 d (c+d x)^{3/4}}{55 (b c-a d)^2 (a+b x)^{11/4}}-\frac {128 d^2 (c+d x)^{3/4}}{385 (b c-a d)^3 (a+b x)^{7/4}}-\frac {\left (128 d^3\right ) \int \frac {1}{(a+b x)^{7/4} \sqrt [4]{c+d x}} \, dx}{385 (b c-a d)^3} \\ & = -\frac {4 (c+d x)^{3/4}}{15 (b c-a d) (a+b x)^{15/4}}+\frac {16 d (c+d x)^{3/4}}{55 (b c-a d)^2 (a+b x)^{11/4}}-\frac {128 d^2 (c+d x)^{3/4}}{385 (b c-a d)^3 (a+b x)^{7/4}}+\frac {512 d^3 (c+d x)^{3/4}}{1155 (b c-a d)^4 (a+b x)^{3/4}} \\ \end{align*}
Time = 0.89 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.87 \[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\frac {4 (c+d x)^{3/4} \left (385 a^3 d^3+165 a^2 b d^2 (-3 c+4 d x)+15 a b^2 d \left (21 c^2-24 c d x+32 d^2 x^2\right )+b^3 \left (-77 c^3+84 c^2 d x-96 c d^2 x^2+128 d^3 x^3\right )\right )}{1155 (b c-a d)^4 (a+b x)^{15/4}} \]
[In]
[Out]
Time = 0.68 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.26
method | result | size |
gosper | \(\frac {4 \left (d x +c \right )^{\frac {3}{4}} \left (128 d^{3} x^{3} b^{3}+480 x^{2} a \,b^{2} d^{3}-96 x^{2} b^{3} c \,d^{2}+660 x \,a^{2} b \,d^{3}-360 x a \,b^{2} c \,d^{2}+84 x \,b^{3} c^{2} d +385 a^{3} d^{3}-495 a^{2} b c \,d^{2}+315 a \,b^{2} c^{2} d -77 b^{3} c^{3}\right )}{1155 \left (b x +a \right )^{\frac {15}{4}} \left (a^{4} d^{4}-4 a^{3} b c \,d^{3}+6 a^{2} b^{2} c^{2} d^{2}-4 a \,b^{3} c^{3} d +b^{4} c^{4}\right )}\) | \(171\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 419 vs. \(2 (112) = 224\).
Time = 1.10 (sec) , antiderivative size = 419, normalized size of antiderivative = 3.08 \[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\frac {4 \, {\left (128 \, b^{3} d^{3} x^{3} - 77 \, b^{3} c^{3} + 315 \, a b^{2} c^{2} d - 495 \, a^{2} b c d^{2} + 385 \, a^{3} d^{3} - 96 \, {\left (b^{3} c d^{2} - 5 \, a b^{2} d^{3}\right )} x^{2} + 12 \, {\left (7 \, b^{3} c^{2} d - 30 \, a b^{2} c d^{2} + 55 \, a^{2} b d^{3}\right )} x\right )} {\left (b x + a\right )}^{\frac {1}{4}} {\left (d x + c\right )}^{\frac {3}{4}}}{1155 \, {\left (a^{4} b^{4} c^{4} - 4 \, a^{5} b^{3} c^{3} d + 6 \, a^{6} b^{2} c^{2} d^{2} - 4 \, a^{7} b c d^{3} + a^{8} d^{4} + {\left (b^{8} c^{4} - 4 \, a b^{7} c^{3} d + 6 \, a^{2} b^{6} c^{2} d^{2} - 4 \, a^{3} b^{5} c d^{3} + a^{4} b^{4} d^{4}\right )} x^{4} + 4 \, {\left (a b^{7} c^{4} - 4 \, a^{2} b^{6} c^{3} d + 6 \, a^{3} b^{5} c^{2} d^{2} - 4 \, a^{4} b^{4} c d^{3} + a^{5} b^{3} d^{4}\right )} x^{3} + 6 \, {\left (a^{2} b^{6} c^{4} - 4 \, a^{3} b^{5} c^{3} d + 6 \, a^{4} b^{4} c^{2} d^{2} - 4 \, a^{5} b^{3} c d^{3} + a^{6} b^{2} d^{4}\right )} x^{2} + 4 \, {\left (a^{3} b^{5} c^{4} - 4 \, a^{4} b^{4} c^{3} d + 6 \, a^{5} b^{3} c^{2} d^{2} - 4 \, a^{6} b^{2} c d^{3} + a^{7} b d^{4}\right )} x\right )}} \]
[In]
[Out]
Timed out. \[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {19}{4}} {\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
[In]
[Out]
\[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\int { \frac {1}{{\left (b x + a\right )}^{\frac {19}{4}} {\left (d x + c\right )}^{\frac {1}{4}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {1}{(a+b x)^{19/4} \sqrt [4]{c+d x}} \, dx=\int \frac {1}{{\left (a+b\,x\right )}^{19/4}\,{\left (c+d\,x\right )}^{1/4}} \,d x \]
[In]
[Out]